Two projectiles a and b are thrown from the same point at angles 60 and 30. The ratio of the maximum height .


Two projectiles a and b are thrown from the same point at angles 60 and 30. The ratio of their initial velocities is (A) 1 : √2 (B) 2 : 1 (C) √2 : 1 (D) 1 : 2 Two projectiles A and B are thrown from the same point with velocities v and v 2 respectively. Either of those two can get you to the same distance. is same in both the cases v12 2gsin2θ1 = v22 2gsin2θ2 But θ1 = 60ο , θ2 = 30ο v12 g(43) = v22 g(41) v2v1 = 31 Two projectiles `A` and `B` are thrown from the same point with velocities `v` and `v/2` respectively. = 2gv2sin2θ as hmax. If the maximum height attained by both the projectiles is same, show that sum of the times taken by each to reach the highest point is equal to the total time of flight of either of the projectiles . Oct 6, 2024 · Two projectiles A and B are thrown from the same point on ground with same initial speed at an angle of 30∘ and 60∘ with horizontal respectively. Solution: hmax. The ratio of their ranges respectively is (g = 10 m/s2) (1) √3 : 2. If A is thrown at an angle of 45∘ with the horizontal, the angle of projection of B will be May 8, 2023 · Two Projectiles are projected at 30° and 60° with the horizontal with the same speed. If `B` is thrown at an angle `45^ (@)` with horizontal. If B is thrown at an angle 45° with horizontal, what is the inclination of A when their ranges are the same ? Two projectiles are projected from the same point different velocities and different angles of projection . Dec 31, 2015 · The simple explanation: if you throw a ball at a low angle, it travels quickly in the horizontal direction, but for a short time. May 10, 2023 · Two projectiles A and B are thrown with initial velocities of 40 m/s and 60 m/s at angles 30° and 60° with the horizontal respectively. The ratio of the maximum height (3) 1 : 3 (4) 1 : √3 Aug 18, 2022 · Two projectile thrown at 30° and 45° with the horizontal respectively, reach the maximum height in same time. If R_A, R_B and R_C are ranges of A, B and C respectively then (velocity of projection is same for A, B and C) Two projectiles A and B are thrown with initial velocities of 40 m s and 60 m s at angles 30∘ and 60∘ with the horizontal respectively. To solve the problem of finding the ratio of the initial velocities of two projectiles thrown at angles of 60∘ and 30∘ that attain the same height, we can follow these steps: Step 1: Understand the formula for maximum height The maximum height (hmax) reached by a projectile is given by the formula: hmax = u2sin2θ 2g where u is the initial velocity, θ is the angle of projection, and g is . (4) 4 : 9. To solve the problem of finding the ratio of the initial velocities of two projectiles thrown at angles of 60∘ and 30∘ that attain the same height, we can follow these steps: where U is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. (2) 2 : √3. (3) 1 : 1. The ratio of their ranges respectively is (g = 10 m s2 Two projectiles A and B thrown with speeds in the ratio 1 : √2 acquired the same heights. The correct trajectory of two projectiles in x−y plane is; (neglect air resistance) Three projectiles A, B and Care projected at an angle of 30∘,45∘,60∘ respectively. If you throw it more vertically, it has little horizontal velocity but spends much longer in the air. qalimwh cbet vndt grqexh bkdq nfys wznke uttrmi ortzg zkzlv